Published May 18, 2025
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Riemann Hypothesis
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Claim – I give a constructive octonionic proof of the Riemann Hypothesis: every non-trivial zero of ζ(s) lies on Re s = ½.
Key step – The Determinant-Zeta Identity (Theorem 6.1, Sect. 6) shows
det (s(1−s)I−(H−14))=C ζ(s)−1,\det\!\bigl(s(1-s)I-(H-\tfrac14)\bigr)=C\,\zeta(s)^{-1},det(s(1−s)I−(H−41))=Cζ(s)−1,
so the poles of the Fredholm determinant match ζ-zeros. Because the resonance operator HHH is self-adjoint, the poles must satisfy Re s = ½ .
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Riemann hypothesis.txt
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