Converting from $ \frac{\mu\mathrm{L} \mathrm{O}_2}{10\mathrm{mg} \mathrm{h}}$ to $ \frac{\mathrm{nmol CO}_2}{\mathrm{g} \mathrm{s}}$ and $ \frac{\mu\mathrm{mol} \mathrm{CO}_2}{\mathrm{kg} \mathrm{s}}$, including adjustment for temperature



Subsections

David 2011-10-07