Step 1

Transformed George 2003 measurements back to the measurement temperature using a rearrangement of equation 1 from George, the standardized temperature of $ 15 ^\circ $C stated in the Georgeh table legend, and Q $ _{10} = 2.075$ from George 2003, and the measurement temperature of $ 27 ^\circ $C reported by Allen 1969:

$\displaystyle R_T = R_{15}[\exp(\ln(Q_{10})(T- 15))/10]$

$\displaystyle [11.26, 22.52] * exp(log(2.075)*(27 - 15)/10)$

Now we have the values that we would have expected to find in the Allen paper, except that the units need to be converted back to the original:

$\displaystyle [27.03,54.07] \mathrm{nmol CO}_2 \mathrm{g}^{-1}\mathrm{s}^{-1}$



David 2011-10-07