convert to units in BETYdb, find $ \textrm{k}$

:

$\displaystyle \textrm{k}\times\frac{\mu\mathrm{L} \textrm{O}_2}{10\mathrm{mg}\...
...} \mathrm{h}} = \frac{\mu\mathrm{mol} \mathrm{CO}_2}{\mathrm{kg} \mathrm{s}}$

$\displaystyle k = \frac{\mathrm{g} \mathrm{O}_2}{7.69\times10^5 \mu\mathrm{L}...
...\times 10\mathrm{mg}}{\mathrm{kg}} \times \frac{\mathrm{h}}{3600 \mathrm{s}}= $

$\displaystyle = 1.13$



David 2011-10-07