YES
proof of /hpcwork/ff862203/termcomp26/benchmarks/3qtSX.pl
# AProVE Commit ID: 23a904c96b029b0a549cde0d0d17dbccf967db59 jckassing 20260626 unpublished dirty


Left Termination of the query pattern

balance(g,a)

w.r.t. the given Prolog program could successfully be proven:

(0) Prolog
(1) PrologToPiTRSProof [SOUND, 0 ms]
(2) PiTRS
(3) DependencyPairsProof [EQUIVALENT, 0 ms]
(4) PiDP
(5) DependencyGraphProof [EQUIVALENT, 0 ms]
(6) AND
    (7) PiDP
        (8) UsableRulesProof [EQUIVALENT, 0 ms]
        (9) PiDP
        (10) PiDPToQDPProof [SOUND, 1 ms]
        (11) QDP
        (12) QDPSizeChangeProof [EQUIVALENT, 0 ms]
        (13) YES
    (14) PiDP
        (15) UsableRulesProof [EQUIVALENT, 0 ms]
        (16) PiDP
        (17) PiDPToQDPProof [SOUND, 0 ms]
        (18) QDP
        (19) QDPSizeChangeProof [EQUIVALENT, 0 ms]
        (20) YES


----------------------------------------

(0)
Obligation:
Clauses:

balance(T, TB) :- balance55(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []).
balance55(nil, C, T, T, A, B, A, B, X, X).
balance55(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) :- ','(balance55(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)), balance55(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)).
balance5(nil, C, T, T, A, B, A, B, X, X) :- balance55(nil, C, T, T, A, B, A, B, X, X).
balance5(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) :- balance55(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT).
balance(nil, -(X, X), -(A, B), -(A, B), -(.(','(nil, -(C, C)), T), T)) :- balance5(nil, C, T, T, A, B, A, B, X, X).
balance(tree(L, V, R), -(IH, IT), -(.(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T))), -(HR, TR), -(.(','(nil, -(XX0, XX0)), XX1), NT)) :- balance5(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT).


Query: balance(g,a)
----------------------------------------

(1) PrologToPiTRSProof (SOUND)
We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes:

balance_in_2: (b,f)

balance55_in_10: (b,f,f,b,f,b,f,f,f,b) (b,f,f,f,f,f,f,f,f,f)

Transforming Prolog into the following Term Rewriting System:

Pi-finite rewrite system:
The TRS R consists of the following rules:

   balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []))
   balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB)

The argument filtering Pi contains the following mapping:
balance_in_ga(x1, x2)  =  balance_in_ga(x1)

U1_ga(x1, x2, x3)  =  U1_ga(x3)

balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaagagaaag(x1, x4, x6, x10)

nil  =  nil

balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaagagaaag

tree(x1, x2, x3)  =  tree(x1, x2, x3)

U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaagagaaag(x3, x6, x8, x18, x19)

balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaaaaaaaaa(x1)

balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaaaaaaaaa

U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaaaaaaaaa(x3, x19)

U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaaaaaaaaa(x19)

U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaagagaaag(x19)

[]  =  []

balance_out_ga(x1, x2)  =  balance_out_ga





Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog



----------------------------------------

(2)
Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:

   balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []))
   balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB)

The argument filtering Pi contains the following mapping:
balance_in_ga(x1, x2)  =  balance_in_ga(x1)

U1_ga(x1, x2, x3)  =  U1_ga(x3)

balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaagagaaag(x1, x4, x6, x10)

nil  =  nil

balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaagagaaag

tree(x1, x2, x3)  =  tree(x1, x2, x3)

U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaagagaaag(x3, x6, x8, x18, x19)

balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaaaaaaaaa(x1)

balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaaaaaaaaa

U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaaaaaaaaa(x3, x19)

U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaaaaaaaaa(x19)

U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaagagaaag(x19)

[]  =  []

balance_out_ga(x1, x2)  =  balance_out_ga



----------------------------------------

(3) DependencyPairsProof (EQUIVALENT)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:

   BALANCE_IN_GA(T, TB) -> U1_GA(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []))
   BALANCE_IN_GA(T, TB) -> BALANCE55_IN_GAAGAGAAAG(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])
   BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))
   BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))
   U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAAAAAAAA(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)
   U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAGAGAAAG(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)

The TRS R consists of the following rules:

   balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []))
   balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB)

The argument filtering Pi contains the following mapping:
balance_in_ga(x1, x2)  =  balance_in_ga(x1)

U1_ga(x1, x2, x3)  =  U1_ga(x3)

balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaagagaaag(x1, x4, x6, x10)

nil  =  nil

balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaagagaaag

tree(x1, x2, x3)  =  tree(x1, x2, x3)

U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaagagaaag(x3, x6, x8, x18, x19)

balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaaaaaaaaa(x1)

balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaaaaaaaaa

U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaaaaaaaaa(x3, x19)

U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaaaaaaaaa(x19)

U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaagagaaag(x19)

[]  =  []

balance_out_ga(x1, x2)  =  balance_out_ga

BALANCE_IN_GA(x1, x2)  =  BALANCE_IN_GA(x1)

U1_GA(x1, x2, x3)  =  U1_GA(x3)

BALANCE55_IN_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  BALANCE55_IN_GAAGAGAAAG(x1, x4, x6, x10)

U2_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_GAAGAGAAAG(x3, x6, x8, x18, x19)

BALANCE55_IN_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  BALANCE55_IN_GAAAAAAAAA(x1)

U2_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_GAAAAAAAAA(x3, x19)

U3_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_GAAAAAAAAA(x19)

U3_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_GAAGAGAAAG(x19)


We have to consider all (P,R,Pi)-chains
----------------------------------------

(4)
Obligation:
Pi DP problem:
The TRS P consists of the following rules:

   BALANCE_IN_GA(T, TB) -> U1_GA(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []))
   BALANCE_IN_GA(T, TB) -> BALANCE55_IN_GAAGAGAAAG(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])
   BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))
   BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))
   U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAAAAAAAA(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)
   U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAGAGAAAG(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)

The TRS R consists of the following rules:

   balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []))
   balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB)

The argument filtering Pi contains the following mapping:
balance_in_ga(x1, x2)  =  balance_in_ga(x1)

U1_ga(x1, x2, x3)  =  U1_ga(x3)

balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaagagaaag(x1, x4, x6, x10)

nil  =  nil

balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaagagaaag

tree(x1, x2, x3)  =  tree(x1, x2, x3)

U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaagagaaag(x3, x6, x8, x18, x19)

balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaaaaaaaaa(x1)

balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaaaaaaaaa

U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaaaaaaaaa(x3, x19)

U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaaaaaaaaa(x19)

U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaagagaaag(x19)

[]  =  []

balance_out_ga(x1, x2)  =  balance_out_ga

BALANCE_IN_GA(x1, x2)  =  BALANCE_IN_GA(x1)

U1_GA(x1, x2, x3)  =  U1_GA(x3)

BALANCE55_IN_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  BALANCE55_IN_GAAGAGAAAG(x1, x4, x6, x10)

U2_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_GAAGAGAAAG(x3, x6, x8, x18, x19)

BALANCE55_IN_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  BALANCE55_IN_GAAAAAAAAA(x1)

U2_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_GAAAAAAAAA(x3, x19)

U3_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_GAAAAAAAAA(x19)

U3_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_GAAGAGAAAG(x19)


We have to consider all (P,R,Pi)-chains
----------------------------------------

(5) DependencyGraphProof (EQUIVALENT)
The approximation of the Dependency Graph [LOPSTR] contains 2 SCCs with 5 less nodes.
----------------------------------------

(6)
Complex Obligation (AND)

----------------------------------------

(7)
Obligation:
Pi DP problem:
The TRS P consists of the following rules:

   U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAAAAAAAA(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)
   BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))

The TRS R consists of the following rules:

   balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []))
   balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB)

The argument filtering Pi contains the following mapping:
balance_in_ga(x1, x2)  =  balance_in_ga(x1)

U1_ga(x1, x2, x3)  =  U1_ga(x3)

balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaagagaaag(x1, x4, x6, x10)

nil  =  nil

balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaagagaaag

tree(x1, x2, x3)  =  tree(x1, x2, x3)

U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaagagaaag(x3, x6, x8, x18, x19)

balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaaaaaaaaa(x1)

balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaaaaaaaaa

U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaaaaaaaaa(x3, x19)

U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaaaaaaaaa(x19)

U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaagagaaag(x19)

[]  =  []

balance_out_ga(x1, x2)  =  balance_out_ga

BALANCE55_IN_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  BALANCE55_IN_GAAAAAAAAA(x1)

U2_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_GAAAAAAAAA(x3, x19)


We have to consider all (P,R,Pi)-chains
----------------------------------------

(8) UsableRulesProof (EQUIVALENT)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
----------------------------------------

(9)
Obligation:
Pi DP problem:
The TRS P consists of the following rules:

   U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAAAAAAAA(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)
   BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))

The TRS R consists of the following rules:

   balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)

The argument filtering Pi contains the following mapping:
nil  =  nil

tree(x1, x2, x3)  =  tree(x1, x2, x3)

balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaaaaaaaaa(x1)

balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaaaaaaaaa

U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaaaaaaaaa(x3, x19)

U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaaaaaaaaa(x19)

BALANCE55_IN_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  BALANCE55_IN_GAAAAAAAAA(x1)

U2_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_GAAAAAAAAA(x3, x19)


We have to consider all (P,R,Pi)-chains
----------------------------------------

(10) PiDPToQDPProof (SOUND)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
----------------------------------------

(11)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   U2_GAAAAAAAAA(R, balance55_out_gaaaaaaaaa) -> BALANCE55_IN_GAAAAAAAAA(R)
   BALANCE55_IN_GAAAAAAAAA(tree(L, V, R)) -> U2_GAAAAAAAAA(R, balance55_in_gaaaaaaaaa(L))
   BALANCE55_IN_GAAAAAAAAA(tree(L, V, R)) -> BALANCE55_IN_GAAAAAAAAA(L)

The TRS R consists of the following rules:

   balance55_in_gaaaaaaaaa(nil) -> balance55_out_gaaaaaaaaa
   balance55_in_gaaaaaaaaa(tree(L, V, R)) -> U2_gaaaaaaaaa(R, balance55_in_gaaaaaaaaa(L))
   U2_gaaaaaaaaa(R, balance55_out_gaaaaaaaaa) -> U3_gaaaaaaaaa(balance55_in_gaaaaaaaaa(R))
   U3_gaaaaaaaaa(balance55_out_gaaaaaaaaa) -> balance55_out_gaaaaaaaaa

The set Q consists of the following terms:

   balance55_in_gaaaaaaaaa(x0)
   U2_gaaaaaaaaa(x0, x1)
   U3_gaaaaaaaaa(x0)

We have to consider all (P,Q,R)-chains.
----------------------------------------

(12) QDPSizeChangeProof (EQUIVALENT)
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 

From the DPs we obtained the following set of size-change graphs:
*BALANCE55_IN_GAAAAAAAAA(tree(L, V, R)) -> U2_GAAAAAAAAA(R, balance55_in_gaaaaaaaaa(L))
The graph contains the following edges 1 > 1


*BALANCE55_IN_GAAAAAAAAA(tree(L, V, R)) -> BALANCE55_IN_GAAAAAAAAA(L)
The graph contains the following edges 1 > 1


*U2_GAAAAAAAAA(R, balance55_out_gaaaaaaaaa) -> BALANCE55_IN_GAAAAAAAAA(R)
The graph contains the following edges 1 >= 1


----------------------------------------

(13)
YES

----------------------------------------

(14)
Obligation:
Pi DP problem:
The TRS P consists of the following rules:

   U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAGAGAAAG(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)
   BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))

The TRS R consists of the following rules:

   balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []))
   balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)
   U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB)

The argument filtering Pi contains the following mapping:
balance_in_ga(x1, x2)  =  balance_in_ga(x1)

U1_ga(x1, x2, x3)  =  U1_ga(x3)

balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaagagaaag(x1, x4, x6, x10)

nil  =  nil

balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaagagaaag

tree(x1, x2, x3)  =  tree(x1, x2, x3)

U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaagagaaag(x3, x6, x8, x18, x19)

balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaaaaaaaaa(x1)

balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaaaaaaaaa

U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaaaaaaaaa(x3, x19)

U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaaaaaaaaa(x19)

U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaagagaaag(x19)

[]  =  []

balance_out_ga(x1, x2)  =  balance_out_ga

BALANCE55_IN_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  BALANCE55_IN_GAAGAGAAAG(x1, x4, x6, x10)

U2_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_GAAGAGAAAG(x3, x6, x8, x18, x19)


We have to consider all (P,R,Pi)-chains
----------------------------------------

(15) UsableRulesProof (EQUIVALENT)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
----------------------------------------

(16)
Obligation:
Pi DP problem:
The TRS P consists of the following rules:

   U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAGAGAAAG(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)
   BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))

The TRS R consists of the following rules:

   balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X)
   balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)))
   U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT))
   U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT)

The argument filtering Pi contains the following mapping:
nil  =  nil

tree(x1, x2, x3)  =  tree(x1, x2, x3)

balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_in_gaaaaaaaaa(x1)

balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  balance55_out_gaaaaaaaaa

U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_gaaaaaaaaa(x3, x19)

U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U3_gaaaaaaaaa(x19)

BALANCE55_IN_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10)  =  BALANCE55_IN_GAAGAGAAAG(x1, x4, x6, x10)

U2_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)  =  U2_GAAGAGAAAG(x3, x6, x8, x18, x19)


We have to consider all (P,R,Pi)-chains
----------------------------------------

(17) PiDPToQDPProof (SOUND)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
----------------------------------------

(18)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   U2_GAAGAGAAAG(R, NT, TR, IT, balance55_out_gaaaaaaaaa) -> BALANCE55_IN_GAAGAGAAAG(R, NT, TR, IT)
   BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), NT, TR, IT) -> U2_GAAGAGAAAG(R, NT, TR, IT, balance55_in_gaaaaaaaaa(L))

The TRS R consists of the following rules:

   balance55_in_gaaaaaaaaa(nil) -> balance55_out_gaaaaaaaaa
   balance55_in_gaaaaaaaaa(tree(L, V, R)) -> U2_gaaaaaaaaa(R, balance55_in_gaaaaaaaaa(L))
   U2_gaaaaaaaaa(R, balance55_out_gaaaaaaaaa) -> U3_gaaaaaaaaa(balance55_in_gaaaaaaaaa(R))
   U3_gaaaaaaaaa(balance55_out_gaaaaaaaaa) -> balance55_out_gaaaaaaaaa

The set Q consists of the following terms:

   balance55_in_gaaaaaaaaa(x0)
   U2_gaaaaaaaaa(x0, x1)
   U3_gaaaaaaaaa(x0)

We have to consider all (P,Q,R)-chains.
----------------------------------------

(19) QDPSizeChangeProof (EQUIVALENT)
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 

From the DPs we obtained the following set of size-change graphs:
*BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), NT, TR, IT) -> U2_GAAGAGAAAG(R, NT, TR, IT, balance55_in_gaaaaaaaaa(L))
The graph contains the following edges 1 > 1, 2 >= 2, 3 >= 3, 4 >= 4


*U2_GAAGAGAAAG(R, NT, TR, IT, balance55_out_gaaaaaaaaa) -> BALANCE55_IN_GAAGAGAAAG(R, NT, TR, IT)
The graph contains the following edges 1 >= 1, 2 >= 2, 3 >= 3, 4 >= 4


----------------------------------------

(20)
YES
