YES
proof of /hpcwork/ff862203/termcomp26/benchmarks/NOhFt.pl
# AProVE Commit ID: 23a904c96b029b0a549cde0d0d17dbccf967db59 jckassing 20260626 unpublished dirty


Left Termination of the query pattern

flatten(g,a)

w.r.t. the given Prolog program could successfully be proven:

(0) Prolog
(1) PrologToPiTRSProof [SOUND, 0 ms]
(2) PiTRS
(3) DependencyPairsProof [EQUIVALENT, 0 ms]
(4) PiDP
(5) DependencyGraphProof [EQUIVALENT, 0 ms]
(6) PiDP
(7) UsableRulesProof [EQUIVALENT, 0 ms]
(8) PiDP
(9) PiDPToQDPProof [SOUND, 0 ms]
(10) QDP
(11) UsableRulesReductionPairsProof [EQUIVALENT, 11 ms]
(12) QDP
(13) PisEmptyProof [EQUIVALENT, 0 ms]
(14) YES


----------------------------------------

(0)
Obligation:
Clauses:

flatten(atom(X), .(X, [])).
flatten(cons(atom(X), U), .(X, Y)) :- flatten(U, Y).
flatten(cons(cons(U, V), W), X) :- flatten(cons(U, cons(V, W)), X).


Query: flatten(g,a)
----------------------------------------

(1) PrologToPiTRSProof (SOUND)
We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes:

flatten_in_2: (b,f)

Transforming Prolog into the following Term Rewriting System:

Pi-finite rewrite system:
The TRS R consists of the following rules:

   flatten_in_ga(atom(X), .(X, [])) -> flatten_out_ga(atom(X), .(X, []))
   flatten_in_ga(cons(atom(X), U), .(X, Y)) -> U1_ga(X, U, Y, flatten_in_ga(U, Y))
   flatten_in_ga(cons(cons(U, V), W), X) -> U2_ga(U, V, W, X, flatten_in_ga(cons(U, cons(V, W)), X))
   U2_ga(U, V, W, X, flatten_out_ga(cons(U, cons(V, W)), X)) -> flatten_out_ga(cons(cons(U, V), W), X)
   U1_ga(X, U, Y, flatten_out_ga(U, Y)) -> flatten_out_ga(cons(atom(X), U), .(X, Y))

The argument filtering Pi contains the following mapping:
flatten_in_ga(x1, x2)  =  flatten_in_ga(x1)

atom(x1)  =  atom(x1)

flatten_out_ga(x1, x2)  =  flatten_out_ga(x1, x2)

cons(x1, x2)  =  cons(x1, x2)

U1_ga(x1, x2, x3, x4)  =  U1_ga(x1, x2, x4)

U2_ga(x1, x2, x3, x4, x5)  =  U2_ga(x1, x2, x3, x5)

.(x1, x2)  =  .(x1, x2)





Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog



----------------------------------------

(2)
Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:

   flatten_in_ga(atom(X), .(X, [])) -> flatten_out_ga(atom(X), .(X, []))
   flatten_in_ga(cons(atom(X), U), .(X, Y)) -> U1_ga(X, U, Y, flatten_in_ga(U, Y))
   flatten_in_ga(cons(cons(U, V), W), X) -> U2_ga(U, V, W, X, flatten_in_ga(cons(U, cons(V, W)), X))
   U2_ga(U, V, W, X, flatten_out_ga(cons(U, cons(V, W)), X)) -> flatten_out_ga(cons(cons(U, V), W), X)
   U1_ga(X, U, Y, flatten_out_ga(U, Y)) -> flatten_out_ga(cons(atom(X), U), .(X, Y))

The argument filtering Pi contains the following mapping:
flatten_in_ga(x1, x2)  =  flatten_in_ga(x1)

atom(x1)  =  atom(x1)

flatten_out_ga(x1, x2)  =  flatten_out_ga(x1, x2)

cons(x1, x2)  =  cons(x1, x2)

U1_ga(x1, x2, x3, x4)  =  U1_ga(x1, x2, x4)

U2_ga(x1, x2, x3, x4, x5)  =  U2_ga(x1, x2, x3, x5)

.(x1, x2)  =  .(x1, x2)



----------------------------------------

(3) DependencyPairsProof (EQUIVALENT)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:

   FLATTEN_IN_GA(cons(atom(X), U), .(X, Y)) -> U1_GA(X, U, Y, flatten_in_ga(U, Y))
   FLATTEN_IN_GA(cons(atom(X), U), .(X, Y)) -> FLATTEN_IN_GA(U, Y)
   FLATTEN_IN_GA(cons(cons(U, V), W), X) -> U2_GA(U, V, W, X, flatten_in_ga(cons(U, cons(V, W)), X))
   FLATTEN_IN_GA(cons(cons(U, V), W), X) -> FLATTEN_IN_GA(cons(U, cons(V, W)), X)

The TRS R consists of the following rules:

   flatten_in_ga(atom(X), .(X, [])) -> flatten_out_ga(atom(X), .(X, []))
   flatten_in_ga(cons(atom(X), U), .(X, Y)) -> U1_ga(X, U, Y, flatten_in_ga(U, Y))
   flatten_in_ga(cons(cons(U, V), W), X) -> U2_ga(U, V, W, X, flatten_in_ga(cons(U, cons(V, W)), X))
   U2_ga(U, V, W, X, flatten_out_ga(cons(U, cons(V, W)), X)) -> flatten_out_ga(cons(cons(U, V), W), X)
   U1_ga(X, U, Y, flatten_out_ga(U, Y)) -> flatten_out_ga(cons(atom(X), U), .(X, Y))

The argument filtering Pi contains the following mapping:
flatten_in_ga(x1, x2)  =  flatten_in_ga(x1)

atom(x1)  =  atom(x1)

flatten_out_ga(x1, x2)  =  flatten_out_ga(x1, x2)

cons(x1, x2)  =  cons(x1, x2)

U1_ga(x1, x2, x3, x4)  =  U1_ga(x1, x2, x4)

U2_ga(x1, x2, x3, x4, x5)  =  U2_ga(x1, x2, x3, x5)

.(x1, x2)  =  .(x1, x2)

FLATTEN_IN_GA(x1, x2)  =  FLATTEN_IN_GA(x1)

U1_GA(x1, x2, x3, x4)  =  U1_GA(x1, x2, x4)

U2_GA(x1, x2, x3, x4, x5)  =  U2_GA(x1, x2, x3, x5)


We have to consider all (P,R,Pi)-chains
----------------------------------------

(4)
Obligation:
Pi DP problem:
The TRS P consists of the following rules:

   FLATTEN_IN_GA(cons(atom(X), U), .(X, Y)) -> U1_GA(X, U, Y, flatten_in_ga(U, Y))
   FLATTEN_IN_GA(cons(atom(X), U), .(X, Y)) -> FLATTEN_IN_GA(U, Y)
   FLATTEN_IN_GA(cons(cons(U, V), W), X) -> U2_GA(U, V, W, X, flatten_in_ga(cons(U, cons(V, W)), X))
   FLATTEN_IN_GA(cons(cons(U, V), W), X) -> FLATTEN_IN_GA(cons(U, cons(V, W)), X)

The TRS R consists of the following rules:

   flatten_in_ga(atom(X), .(X, [])) -> flatten_out_ga(atom(X), .(X, []))
   flatten_in_ga(cons(atom(X), U), .(X, Y)) -> U1_ga(X, U, Y, flatten_in_ga(U, Y))
   flatten_in_ga(cons(cons(U, V), W), X) -> U2_ga(U, V, W, X, flatten_in_ga(cons(U, cons(V, W)), X))
   U2_ga(U, V, W, X, flatten_out_ga(cons(U, cons(V, W)), X)) -> flatten_out_ga(cons(cons(U, V), W), X)
   U1_ga(X, U, Y, flatten_out_ga(U, Y)) -> flatten_out_ga(cons(atom(X), U), .(X, Y))

The argument filtering Pi contains the following mapping:
flatten_in_ga(x1, x2)  =  flatten_in_ga(x1)

atom(x1)  =  atom(x1)

flatten_out_ga(x1, x2)  =  flatten_out_ga(x1, x2)

cons(x1, x2)  =  cons(x1, x2)

U1_ga(x1, x2, x3, x4)  =  U1_ga(x1, x2, x4)

U2_ga(x1, x2, x3, x4, x5)  =  U2_ga(x1, x2, x3, x5)

.(x1, x2)  =  .(x1, x2)

FLATTEN_IN_GA(x1, x2)  =  FLATTEN_IN_GA(x1)

U1_GA(x1, x2, x3, x4)  =  U1_GA(x1, x2, x4)

U2_GA(x1, x2, x3, x4, x5)  =  U2_GA(x1, x2, x3, x5)


We have to consider all (P,R,Pi)-chains
----------------------------------------

(5) DependencyGraphProof (EQUIVALENT)
The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 2 less nodes.
----------------------------------------

(6)
Obligation:
Pi DP problem:
The TRS P consists of the following rules:

   FLATTEN_IN_GA(cons(cons(U, V), W), X) -> FLATTEN_IN_GA(cons(U, cons(V, W)), X)
   FLATTEN_IN_GA(cons(atom(X), U), .(X, Y)) -> FLATTEN_IN_GA(U, Y)

The TRS R consists of the following rules:

   flatten_in_ga(atom(X), .(X, [])) -> flatten_out_ga(atom(X), .(X, []))
   flatten_in_ga(cons(atom(X), U), .(X, Y)) -> U1_ga(X, U, Y, flatten_in_ga(U, Y))
   flatten_in_ga(cons(cons(U, V), W), X) -> U2_ga(U, V, W, X, flatten_in_ga(cons(U, cons(V, W)), X))
   U2_ga(U, V, W, X, flatten_out_ga(cons(U, cons(V, W)), X)) -> flatten_out_ga(cons(cons(U, V), W), X)
   U1_ga(X, U, Y, flatten_out_ga(U, Y)) -> flatten_out_ga(cons(atom(X), U), .(X, Y))

The argument filtering Pi contains the following mapping:
flatten_in_ga(x1, x2)  =  flatten_in_ga(x1)

atom(x1)  =  atom(x1)

flatten_out_ga(x1, x2)  =  flatten_out_ga(x1, x2)

cons(x1, x2)  =  cons(x1, x2)

U1_ga(x1, x2, x3, x4)  =  U1_ga(x1, x2, x4)

U2_ga(x1, x2, x3, x4, x5)  =  U2_ga(x1, x2, x3, x5)

.(x1, x2)  =  .(x1, x2)

FLATTEN_IN_GA(x1, x2)  =  FLATTEN_IN_GA(x1)


We have to consider all (P,R,Pi)-chains
----------------------------------------

(7) UsableRulesProof (EQUIVALENT)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
----------------------------------------

(8)
Obligation:
Pi DP problem:
The TRS P consists of the following rules:

   FLATTEN_IN_GA(cons(cons(U, V), W), X) -> FLATTEN_IN_GA(cons(U, cons(V, W)), X)
   FLATTEN_IN_GA(cons(atom(X), U), .(X, Y)) -> FLATTEN_IN_GA(U, Y)

R is empty.
The argument filtering Pi contains the following mapping:
atom(x1)  =  atom(x1)

cons(x1, x2)  =  cons(x1, x2)

.(x1, x2)  =  .(x1, x2)

FLATTEN_IN_GA(x1, x2)  =  FLATTEN_IN_GA(x1)


We have to consider all (P,R,Pi)-chains
----------------------------------------

(9) PiDPToQDPProof (SOUND)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
----------------------------------------

(10)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   FLATTEN_IN_GA(cons(cons(U, V), W)) -> FLATTEN_IN_GA(cons(U, cons(V, W)))
   FLATTEN_IN_GA(cons(atom(X), U)) -> FLATTEN_IN_GA(U)

R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
----------------------------------------

(11) UsableRulesReductionPairsProof (EQUIVALENT)
By using the usable rules with reduction pair processor [LPAR04] with a polynomial ordering [POLO], all dependency pairs and the corresponding usable rules [FROCOS05] can be oriented non-strictly. All non-usable rules are removed, and those dependency pairs and usable rules that have been oriented strictly or contain non-usable symbols in their left-hand side are removed as well.

The following dependency pairs can be deleted:

   FLATTEN_IN_GA(cons(cons(U, V), W)) -> FLATTEN_IN_GA(cons(U, cons(V, W)))
   FLATTEN_IN_GA(cons(atom(X), U)) -> FLATTEN_IN_GA(U)
No rules are removed from R.

Used ordering: POLO with Polynomial interpretation [POLO]:

   POL(FLATTEN_IN_GA(x_1)) = 2*x_1
   POL(atom(x_1)) = x_1
   POL(cons(x_1, x_2)) = 1 + 2*x_1 + x_2


----------------------------------------

(12)
Obligation:
Q DP problem:
P is empty.
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
----------------------------------------

(13) PisEmptyProof (EQUIVALENT)
The TRS P is empty. Hence, there is no (P,Q,R) chain.
----------------------------------------

(14)
YES
