Q: Given the following code slice:
```
1 static int __fib6_rule_action(struct fib_rule *rule, struct flowi *flp,
2 			      int flags, struct fib_lookup_arg *arg)
3 {
4 	struct fib6_result *res = arg->result;
5 	struct flowi6 *flp6 = &flp->u.ip6;
6 	struct rt6_info *rt = NULL;
7 	struct fib6_table *table;
8 	struct net *net = rule->fr_net;
9 	pol_lookup_t lookup = arg->lookup_ptr;
10 	int err = 0;
11 	u32 tb_id;
12 
13 	switch (rule->action) {
14 	case FR_ACT_TO_TBL:
15 		break;
16 	case FR_ACT_UNREACHABLE:
17 		err = -ENETUNREACH;
18 		rt = net->ipv6.ip6_null_entry;
19 		goto discard_pkt;
20 	default:
21 	case FR_ACT_BLACKHOLE:
22 		err = -EINVAL;
23 		rt = net->ipv6.ip6_blk_hole_entry;
24 		goto discard_pkt;
25 	case FR_ACT_PROHIBIT:
26 		err = -EACCES;
27 		rt = net->ipv6.ip6_prohibit_entry;
28 		goto discard_pkt;
29 	}
30 
31 	tb_id = fib_rule_get_table(rule, arg);
32 	table = fib6_get_table(net, tb_id);
33 	if (!table) {
34 		err = -EAGAIN;
35 		goto out;
36 	}
37 
38 	rt = pol_lookup_func(lookup,
39 			     net, table, flp6, arg->lookup_data, flags);
40 	if (rt != net->ipv6.ip6_null_entry) {
41 		err = fib6_rule_saddr(net, rule, flags, flp6,
42 				      ip6_dst_idev(&rt->dst)->dev);
43 
44 		if (err == -EAGAIN)
45 			goto again;
46 
47 		err = rt->dst.error;
48 		if (err != -EAGAIN)
49 			goto out;
50 	}
51 again:
52 	ip6_rt_put_flags(rt, flags);
53 	err = -EAGAIN;
54 	rt = NULL;
55 	goto out;
56 
57 discard_pkt:
58 	if (!(flags & RT6_LOOKUP_F_DST_NOREF))
59 		dst_hold(&rt->dst);
60 out:
61 	res->rt6 = rt;
62 	return err;
63 }
```
which has a vulnerability among CWE-476 and among lines:
```
32 	table = fib6_get_table(net, tb_id);
```
Please generate five possible patches for the vulnerability.