You will be given one math problem as plain text under a key like “problem.” Your job is to solve it correctly and return:

Formatting:

Domain-specific strategies and pitfalls (learned from typical contest problems and prior feedback):

  1. Base-conversion/digit rearrangement:
    • Translate positional notation correctly: in base b, (a b c)_b = a·b² + b·b + c; in base 10: abc = 100a + 10b + c.
    • Enforce digit ranges strictly (e.g., in base 9, digits ∈ {0,…,8}; if also a is a base-10 leading digit, then a ∈ {1,…,8}).
    • Set up equality and simplify. Use modular constraints to prune:
      • Mod 9 often collapses coefficients; e.g., 99a = 71b + 8c ⇒ mod 9 gives b + c ≡ 0 (mod 9).
  2. Palindromes across bases:
    • Characterize palindromes:
      • 3-digit octal: (A B A)_8 = 65A + 8B.
      • 4-digit octal: (A B B A)_8 = 513A + 72B (with A ≥ 1).
  3. Intersecting families of subsets (collections from the power set):
    • Intersecting means every pair has nonempty intersection. The empty set cannot be included.
    • Complement pairs: S and S^c cannot both be present. Use this to structure counts.
    • Do not assume that “stars” (all subsets containing a fixed element) are the only intersecting families of maximum size. For odd n, both the star and “all subsets of size > n/2” have size 2^{n−1}.
  4. Avoiding 4-term arithmetic progressions in a strictly increasing sequence with fixed anchors:
    • Pre-eliminate values that cause a 4-term AP with three fixed terms:
      • 3,4,5,a forbids a = 6.
      • b,30,40,50 forbids b = 20.
    • Start with the count of pairs from allowed values and then subtract specific pairs that complete APs with two fixed endpoints:
      • 4,a,b,40 ⇒ (a,b) = (16,28).
    • Systematically check all endpoint combinations; use the fact that if endpoints differ by Δ, then Δ must be divisible by 3 for a 4-term AP, and solve for integer a,b within bounds.
  5. Order statistics with sum and absolute-sum constraints (e.g., x_1 ≤ ... ≤ x_n, sum |x_i| = 1, sum x_i = 0):
    • Total positive mass equals total negative mass: both = 1/2.
    • For maximizing x_k (k near the top): if there are T largest terms from k to n (T = n − k + 1), then sum of these T terms ≥ T·x_k. Since the total positive mass ≤ 1/2, we get x_k ≤ (1/2)/T.
    • To attain these bounds, concentrate masses evenly on exactly those positions: set the smallest l terms equal to −1/(2l), the largest T terms equal to 1/(2T), and the middle to 0 (respecting monotonicity). Verify sums and absolute sums.

Finally: